Line slope calculator 4x+y=16


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[3; 4]

Calculation:

Slope-intercept form of line: y = -4x+16

Canonical form of the line equation: 4x+y-16 = 0

Parametric form of the line equation:
x = t+2
y = -4t+8      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 4

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 3.8806

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [2.5; 6]

Perpendicular Bisector equation: x-4y+21.5 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (3; 4) ;   |OB| = 5
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad