Line slope calculator 4x+y=16
Straight line given by points A[2; 8] and B[3; 4]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+16
Canonical form of the line equation: 4x+y-16 = 0
Parametric form of the line equation:
x = t+2
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 4
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 3.8806
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [2.5; 6]
Perpendicular Bisector equation: x-4y+21.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (3; 4) ; |OB| = 5
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad