Line slope calculator 3x+y=14
Straight line given by points A[2; 8] and B[3; 5]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+14
Canonical form of the line equation: 3x+y-14 = 0
Parametric form of the line equation:
x = t+2
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 4.6667
Y intercept: y0 = q = 14
Distance line from the origin: d0 = 4.4272
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [2.5; 6.5]
Perpendicular Bisector equation: x-3y+17 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (3; 5) ; |OB| = 5.831
Scalar product OA .OB = 46
Angle ∠ AOB = 16°55'39″ = 0.2954 rad