Line slope calculator 5x+2y=26


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -2.5x+13

Canonical form of the line equation: 5x+2y-26 = 0

Parametric form of the line equation:
x = 2t+2
y = -5t+8      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 5.2

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 4.8281

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [3; 5.5]

Perpendicular Bisector equation: 2x-5y+21.5 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 32
Angle ∠ AOB = 39°5'38″ = 0.6823 rad