Line slope calculator 8x+3y=40
Straight line given by points A[2; 8] and B[5; 0]
Calculation:
Slope: m = -2.6667Slope-intercept form of line: y = -2.6667x+13.3333
Canonical form of the line equation: 8x+3y-40 = 0
Parametric form of the line equation:
x = 3t+2
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -69°26'38″ = -1.212 rad
X intercept: x0 = 5
Y intercept: y0 = q = 13.3333
Distance line from the origin: d0 = 4.6816
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; -8)
Normal vector: n = (8; 3)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 3x-8y+21.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 10
Angle ∠ AOB = 75°57'50″ = 1.3258 rad