Line slope calculator 7x+3y=38


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -2.3333x+12.6667

Canonical form of the line equation: 7x+3y-38 = 0

Parametric form of the line equation:
x = 3t+2
y = -7t+8      ; t ∈ R

Slope: m = -2.3333

Slope angle of line: φ = -66°48'5″ = -1.1659 rad

X intercept: x0 = 5.4286

Y intercept: y0 = q = 12.6667

Distance line from the origin: d0 = 4.9896

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; -7)

Normal vector: n = (7; 3)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 3x-7y+21 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 18
Angle ∠ AOB = 64°39'14″ = 1.1284 rad