Line slope calculator 2x+3y=28
Straight line given by points A[2; 8] and B[5; 6]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+9.3333
Canonical form of the line equation: 2x+3y-28 = 0
Parametric form of the line equation:
x = 3t+2
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 14
Y intercept: y0 = q = 9.3333
Distance line from the origin: d0 = 7.7658
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [3.5; 7]
Perpendicular Bisector equation: 3x-2y+3.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 58
Angle ∠ AOB = 25°46'10″ = 0.4498 rad