Line slope calculator 2x-4y=-28


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[6; 10]

Calculation:

Slope-intercept form of line: y = 0.5x+7

Canonical form of the line equation: 2x-4y+28 = 0

Parametric form of the line equation:
x = 4t+2
y = 2t+8      ; t ∈ R

Slope: m = 0.5

Slope angle of line: φ = 26°33'54″ = 0.4636 rad

X intercept: x0 = -14

Y intercept: y0 = q = 7

Distance line from the origin: d0 = 6.261

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; 2)

Normal vector: n = (2; -4)

Midpoint of the segment AB: M = [4; 9]

Perpendicular Bisector equation: 4x+2y-34 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (6; 10) ;   |OB| = 11.6619
Scalar product OA .OB = 92
Angle ∠ AOB = 16°55'39″ = 0.2954 rad