Line slope calculator 5x+4y=42


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[6; 3]

Calculation:

Slope-intercept form of line: y = -1.25x+10.5

Canonical form of the line equation: 5x+4y-42 = 0

Parametric form of the line equation:
x = 4t+2
y = -5t+8      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 8.4

Y intercept: y0 = q = 10.5

Distance line from the origin: d0 = 6.5593

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 4x-5y+11.5 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 36
Angle ∠ AOB = 49°23'55″ = 0.8622 rad