Line slope calculator 3x+4y=38
Straight line given by points A[2; 8] and B[6; 5]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+9.5
Canonical form of the line equation: 3x+4y-38 = 0
Parametric form of the line equation:
x = 4t+2
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 12.6667
Y intercept: y0 = q = 9.5
Distance line from the origin: d0 = 7.6
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [4; 6.5]
Perpendicular Bisector equation: 4x-3y+3.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 52
Angle ∠ AOB = 36°9'29″ = 0.6311 rad