Line slope calculator 2x+4y=36


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[6; 6]

Calculation:

Slope-intercept form of line: y = -0.5x+9

Canonical form of the line equation: 2x+4y-36 = 0

Parametric form of the line equation:
x = 4t+2
y = -2t+8      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 18

Y intercept: y0 = q = 9

Distance line from the origin: d0 = 8.0498

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; -2)

Normal vector: n = (2; 4)

Midpoint of the segment AB: M = [4; 7]

Perpendicular Bisector equation: 4x-2y-2 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (6; 6) ;   |OB| = 8.4853
Scalar product OA .OB = 60
Angle ∠ AOB = 30°57'50″ = 0.5404 rad