Line slope calculator 4x+5y=48


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[7; 4]

Calculation:

Slope-intercept form of line: y = -0.8x+9.6

Canonical form of the line equation: 4x+5y-48 = 0

Parametric form of the line equation:
x = 5t+2
y = -4t+8      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 12

Y intercept: y0 = q = 9.6

Distance line from the origin: d0 = 7.4963

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [4.5; 6]

Perpendicular Bisector equation: 5x-4y+1.5 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (7; 4) ;   |OB| = 8.0623
Scalar product OA .OB = 46
Angle ∠ AOB = 46°13'8″ = 0.8067 rad