Line slope calculator 7x+6y=62
Straight line given by points A[2; 8] and B[8; 1]
Calculation:
Slope: m = -1.1667Slope-intercept form of line: y = -1.1667x+10.3333
Canonical form of the line equation: 7x+6y-62 = 0
Parametric form of the line equation:
x = 6t+2
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -49°23'55″ = -0.8622 rad
X intercept: x0 = 8.8571
Y intercept: y0 = q = 10.3333
Distance line from the origin: d0 = 6.7248
The length of the segment AB: |AB| = 9.2195
Vector: AB = (6; -7)
Normal vector: n = (7; 6)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 6x-7y+1.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 24
Angle ∠ AOB = 68°50'19″ = 1.2015 rad