Line slope calculator 5x+6y=58
Straight line given by points A[2; 8] and B[8; 3]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+9.6667
Canonical form of the line equation: 5x+6y-58 = 0
Parametric form of the line equation:
x = 6t+2
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 11.6
Y intercept: y0 = q = 9.6667
Distance line from the origin: d0 = 7.4261
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [5; 5.5]
Perpendicular Bisector equation: 6x-5y-2.5 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 40
Angle ∠ AOB = 55°24'28″ = 0.967 rad