Line slope calculator 2x+6y=52
Straight line given by points A[2; 8] and B[8; 6]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+8.6667
Canonical form of the line equation: 2x+6y-52 = 0
Parametric form of the line equation:
x = 6t+2
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 26
Y intercept: y0 = q = 8.6667
Distance line from the origin: d0 = 8.2219
The length of the segment AB: |AB| = 6.3246
Vector: AB = (6; -2)
Normal vector: n = (2; 6)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 6x-2y-16 = 0
Vector OA = (2; 8) ; |OA| = 8.2462
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 64
Angle ∠ AOB = 39°5'38″ = 0.6823 rad