Line slope calculator 3x+7y=62


Enter coordinates of two different points:

Straight line given by points A[2; 8] and B[9; 5]

Calculation:

Slope-intercept form of line: y = -0.4286x+8.8571

Canonical form of the line equation: 3x+7y-62 = 0

Parametric form of the line equation:
x = 7t+2
y = -3t+8      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 20.6667

Y intercept: y0 = q = 8.8571

Distance line from the origin: d0 = 8.141

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [5.5; 6.5]

Perpendicular Bisector equation: 7x-3y-19 = 0


Vector OA = (2; 8) ;   |OA| = 8.2462
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 58
Angle ∠ AOB = 46°54'33″ = 0.8187 rad