Line slope calculator 5x-7y=15
Straight line given by points A[3; 0] and B[10; 5]
Calculation:
Slope: m = 0.7143Slope-intercept form of line: y = 0.7143x-2.1429
Canonical form of the line equation: 5x-7y-15 = 0
Parametric form of the line equation:
x = 7t+3
y = 5t ; t ∈ R
Slope angle of line: φ = 35°32'16″ = 0.6202 rad
X intercept: x0 = 3
Y intercept: y0 = q = -2.1429
Distance line from the origin: d0 = 1.7437
The length of the segment AB: |AB| = 8.6023
Vector: AB = (7; 5)
Normal vector: n = (5; -7)
Midpoint of the segment AB: M = [6.5; 2.5]
Perpendicular Bisector equation: 7x+5y-58 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 30
Angle ∠ AOB = 26°33'54″ = 0.4636 rad