Line slope calculator 10x-3y=30
Straight line given by points A[3; 0] and B[6; 10]
Calculation:
Slope: m = 3.3333Slope-intercept form of line: y = 3.3333x-10
Canonical form of the line equation: 10x-3y-30 = 0
Parametric form of the line equation:
x = 3t+3
y = 10t ; t ∈ R
Slope angle of line: φ = 73°18'3″ = 1.2793 rad
X intercept: x0 = 3
Y intercept: y0 = q = -10
Distance line from the origin: d0 = 2.8735
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; 10)
Normal vector: n = (10; -3)
Midpoint of the segment AB: M = [4.5; 5]
Perpendicular Bisector equation: 3x+10y-63.5 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (6; 10) ; |OB| = 11.6619
Scalar product OA .OB = 18
Angle ∠ AOB = 59°2'10″ = 1.0304 rad