Line slope calculator 4x-3y=12


Enter coordinates of two different points:

Straight line given by points A[3; 0] and B[6; 4]

Calculation:

Slope-intercept form of line: y = 1.3333x-4

Canonical form of the line equation: 4x-3y-12 = 0

Parametric form of the line equation:
x = 3t+3
y = 4t      ; t ∈ R

Slope: m = 1.3333

Slope angle of line: φ = 53°7'48″ = 0.9273 rad

X intercept: x0 = 3

Y intercept: y0 = q = -4

Distance line from the origin: d0 = 2.4

The length of the segment AB: |AB| = 5

Vector: AB = (3; 4)

Normal vector: n = (4; -3)

Midpoint of the segment AB: M = [4.5; 2]

Perpendicular Bisector equation: 3x+4y-21.5 = 0


Vector OA = (3; 0) ;   |OA| = 3
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 18
Angle ∠ AOB = 33°41'24″ = 0.588 rad