Line slope calculator 5x-3y=15


Enter coordinates of two different points:

Straight line given by points A[3; 0] and B[6; 5]

Calculation:

Slope-intercept form of line: y = 1.6667x-5

Canonical form of the line equation: 5x-3y-15 = 0

Parametric form of the line equation:
x = 3t+3
y = 5t      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = 3

Y intercept: y0 = q = -5

Distance line from the origin: d0 = 2.5725

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [4.5; 2.5]

Perpendicular Bisector equation: 3x+5y-26 = 0


Vector OA = (3; 0) ;   |OA| = 3
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 18
Angle ∠ AOB = 39°48'20″ = 0.6947 rad