Line slope calculator 5x-4y=15


Enter coordinates of two different points:

Straight line given by points A[3; 0] and B[7; 5]

Calculation:

Slope-intercept form of line: y = 1.25x-3.75

Canonical form of the line equation: 5x-4y-15 = 0

Parametric form of the line equation:
x = 4t+3
y = 5t      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = 3

Y intercept: y0 = q = -3.75

Distance line from the origin: d0 = 2.3426

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [5; 2.5]

Perpendicular Bisector equation: 4x+5y-32.5 = 0


Vector OA = (3; 0) ;   |OA| = 3
Vector OB = (7; 5) ;   |OB| = 8.6023
Scalar product OA .OB = 21
Angle ∠ AOB = 35°32'16″ = 0.6202 rad