Line slope calculator 5x-4y=15
Straight line given by points A[3; 0] and B[7; 5]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-3.75
Canonical form of the line equation: 5x-4y-15 = 0
Parametric form of the line equation:
x = 4t+3
y = 5t ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 3
Y intercept: y0 = q = -3.75
Distance line from the origin: d0 = 2.3426
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [5; 2.5]
Perpendicular Bisector equation: 4x+5y-32.5 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 21
Angle ∠ AOB = 35°32'16″ = 0.6202 rad