Line slope calculator x-5y=3
Straight line given by points A[3; 0] and B[8; 1]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x-0.6
Canonical form of the line equation: x-5y-3 = 0
Parametric form of the line equation:
x = 5t+3
y = t ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = 3
Y intercept: y0 = q = -0.6
Distance line from the origin: d0 = 0.5883
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [5.5; 0.5]
Perpendicular Bisector equation: 5x+y-28 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 24
Angle ∠ AOB = 7°7'30″ = 0.1244 rad