Line slope calculator 3x-5y=9
Straight line given by points A[3; 0] and B[8; 3]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x-1.8
Canonical form of the line equation: 3x-5y-9 = 0
Parametric form of the line equation:
x = 5t+3
y = 3t ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = 3
Y intercept: y0 = q = -1.8
Distance line from the origin: d0 = 1.5435
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [5.5; 1.5]
Perpendicular Bisector equation: 5x+3y-32 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 24
Angle ∠ AOB = 20°33'22″ = 0.3588 rad