Line slope calculator 4x-5y=12
Straight line given by points A[3; 0] and B[8; 4]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x-2.4
Canonical form of the line equation: 4x-5y-12 = 0
Parametric form of the line equation:
x = 5t+3
y = 4t ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = 3
Y intercept: y0 = q = -2.4
Distance line from the origin: d0 = 1.8741
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [5.5; 2]
Perpendicular Bisector equation: 5x+4y-35.5 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (8; 4) ; |OB| = 8.9443
Scalar product OA .OB = 24
Angle ∠ AOB = 26°33'54″ = 0.4636 rad