Line slope calculator 5x-6y=15
Straight line given by points A[3; 0] and B[9; 5]
Calculation:
Slope: m = 0.8333Slope-intercept form of line: y = 0.8333x-2.5
Canonical form of the line equation: 5x-6y-15 = 0
Parametric form of the line equation:
x = 6t+3
y = 5t ; t ∈ R
Slope angle of line: φ = 39°48'20″ = 0.6947 rad
X intercept: x0 = 3
Y intercept: y0 = q = -2.5
Distance line from the origin: d0 = 1.9206
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; 5)
Normal vector: n = (5; -6)
Midpoint of the segment AB: M = [6; 2.5]
Perpendicular Bisector equation: 6x+5y-48.5 = 0
Vector OA = (3; 0) ; |OA| = 3
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 27
Angle ∠ AOB = 29°3'17″ = 0.5071 rad