Line slope calculator x+5y=8


Enter coordinates of two different points:

Straight line given by points A[3; 1] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.2x+1.6

Canonical form of the line equation: x+5y-8 = 0

Parametric form of the line equation:
x = 5t+3
y = -t+1      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 8

Y intercept: y0 = q = 1.6

Distance line from the origin: d0 = 1.5689

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [5.5; 0.5]

Perpendicular Bisector equation: 5x-y-27 = 0


Vector OA = (3; 1) ;   |OA| = 3.1623
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 24
Angle ∠ AOB = 18°26'6″ = 0.3218 rad