Line slope calculator 7x-5y=16


Enter coordinates of two different points:

Straight line given by points A[3; 1] and B[8; 8]

Calculation:

Slope-intercept form of line: y = 1.4x-3.2

Canonical form of the line equation: 7x-5y-16 = 0

Parametric form of the line equation:
x = 5t+3
y = 7t+1      ; t ∈ R

Slope: m = 1.4

Slope angle of line: φ = 54°27'44″ = 0.9505 rad

X intercept: x0 = 2.2857

Y intercept: y0 = q = -3.2

Distance line from the origin: d0 = 1.86

The length of the segment AB: |AB| = 8.6023

Vector: AB = (5; 7)

Normal vector: n = (7; -5)

Midpoint of the segment AB: M = [5.5; 4.5]

Perpendicular Bisector equation: 5x+7y-59 = 0


Vector OA = (3; 1) ;   |OA| = 3.1623
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 32
Angle ∠ AOB = 26°33'54″ = 0.4636 rad