Line slope calculator x+6y=9
Straight line given by points A[3; 1] and B[9; 0]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+1.5
Canonical form of the line equation: x+6y-9 = 0
Parametric form of the line equation:
x = 6t+3
y = -t+1 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 9
Y intercept: y0 = q = 1.5
Distance line from the origin: d0 = 1.4796
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [6; 0.5]
Perpendicular Bisector equation: 6x-y-35.5 = 0
Vector OA = (3; 1) ; |OA| = 3.1623
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 27
Angle ∠ AOB = 18°26'6″ = 0.3218 rad