Line slope calculator 10x+y=40


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 0]

Calculation:

Slope-intercept form of line: y = -10x+40

Canonical form of the line equation: 10x+y-40 = 0

Parametric form of the line equation:
x = t+3
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 4

Y intercept: y0 = q = 40

Distance line from the origin: d0 = 3.9801

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [3.5; 5]

Perpendicular Bisector equation: x-10y+46.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 0) ;   |OB| = 4
Scalar product OA .OB = 12
Angle ∠ AOB = 73°18'3″ = 1.2793 rad