Line slope calculator 7x+y=31


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -7x+31

Canonical form of the line equation: 7x+y-31 = 0

Parametric form of the line equation:
x = t+3
y = -7t+10      ; t ∈ R

Slope: m = -7

Slope angle of line: φ = -81°52'12″ = -1.4289 rad

X intercept: x0 = 4.4286

Y intercept: y0 = q = 31

Distance line from the origin: d0 = 4.3841

The length of the segment AB: |AB| = 7.0711

Vector: AB = (1; -7)

Normal vector: n = (7; 1)

Midpoint of the segment AB: M = [3.5; 6.5]

Perpendicular Bisector equation: x-7y+42 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 42
Angle ∠ AOB = 36°25'51″ = 0.6358 rad