Line slope calculator 7x+y=31
Straight line given by points A[3; 10] and B[4; 3]
Calculation:
Slope: m = -7Slope-intercept form of line: y = -7x+31
Canonical form of the line equation: 7x+y-31 = 0
Parametric form of the line equation:
x = t+3
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -81°52'12″ = -1.4289 rad
X intercept: x0 = 4.4286
Y intercept: y0 = q = 31
Distance line from the origin: d0 = 4.3841
The length of the segment AB: |AB| = 7.0711
Vector: AB = (1; -7)
Normal vector: n = (7; 1)
Midpoint of the segment AB: M = [3.5; 6.5]
Perpendicular Bisector equation: x-7y+42 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (4; 3) ; |OB| = 5
Scalar product OA .OB = 42
Angle ∠ AOB = 36°25'51″ = 0.6358 rad