Line slope calculator 6x+y=28
Straight line given by points A[3; 10] and B[4; 4]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+28
Canonical form of the line equation: 6x+y-28 = 0
Parametric form of the line equation:
x = t+3
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 4.6667
Y intercept: y0 = q = 28
Distance line from the origin: d0 = 4.6032
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [3.5; 7]
Perpendicular Bisector equation: x-6y+38.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (4; 4) ; |OB| = 5.6569
Scalar product OA .OB = 52
Angle ∠ AOB = 28°18'3″ = 0.4939 rad