Line slope calculator 6x+y=28


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 4]

Calculation:

Slope-intercept form of line: y = -6x+28

Canonical form of the line equation: 6x+y-28 = 0

Parametric form of the line equation:
x = t+3
y = -6t+10      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 4.6667

Y intercept: y0 = q = 28

Distance line from the origin: d0 = 4.6032

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [3.5; 7]

Perpendicular Bisector equation: x-6y+38.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 4) ;   |OB| = 5.6569
Scalar product OA .OB = 52
Angle ∠ AOB = 28°18'3″ = 0.4939 rad