Line slope calculator 5x+y=25
Straight line given by points A[3; 10] and B[4; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+25
Canonical form of the line equation: 5x+y-25 = 0
Parametric form of the line equation:
x = t+3
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 5
Y intercept: y0 = q = 25
Distance line from the origin: d0 = 4.9029
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [3.5; 7.5]
Perpendicular Bisector equation: x-5y+34 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 62
Angle ∠ AOB = 21°57'38″ = 0.3833 rad