Line slope calculator 5x+y=25


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 5]

Calculation:

Slope-intercept form of line: y = -5x+25

Canonical form of the line equation: 5x+y-25 = 0

Parametric form of the line equation:
x = t+3
y = -5t+10      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 5

Y intercept: y0 = q = 25

Distance line from the origin: d0 = 4.9029

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [3.5; 7.5]

Perpendicular Bisector equation: x-5y+34 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 5) ;   |OB| = 6.4031
Scalar product OA .OB = 62
Angle ∠ AOB = 21°57'38″ = 0.3833 rad