Line slope calculator 4x+y=22
Straight line given by points A[3; 10] and B[4; 6]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+22
Canonical form of the line equation: 4x+y-22 = 0
Parametric form of the line equation:
x = t+3
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 5.5
Y intercept: y0 = q = 22
Distance line from the origin: d0 = 5.3358
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [3.5; 8]
Perpendicular Bisector equation: x-4y+28.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (4; 6) ; |OB| = 7.2111
Scalar product OA .OB = 72
Angle ∠ AOB = 16°59'27″ = 0.2965 rad