Line slope calculator 4x+y=22


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 6]

Calculation:

Slope-intercept form of line: y = -4x+22

Canonical form of the line equation: 4x+y-22 = 0

Parametric form of the line equation:
x = t+3
y = -4t+10      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 5.5

Y intercept: y0 = q = 22

Distance line from the origin: d0 = 5.3358

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [3.5; 8]

Perpendicular Bisector equation: x-4y+28.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 6) ;   |OB| = 7.2111
Scalar product OA .OB = 72
Angle ∠ AOB = 16°59'27″ = 0.2965 rad