Line slope calculator 2x+y=16


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[4; 8]

Calculation:

Slope-intercept form of line: y = -2x+16

Canonical form of the line equation: 2x+y-16 = 0

Parametric form of the line equation:
x = t+3
y = -2t+10      ; t ∈ R

Slope: m = -2

Slope angle of line: φ = -63°26'6″ = -1.1071 rad

X intercept: x0 = 8

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 7.1554

The length of the segment AB: |AB| = 2.2361

Vector: AB = (1; -2)

Normal vector: n = (2; 1)

Midpoint of the segment AB: M = [3.5; 9]

Perpendicular Bisector equation: x-2y+14.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (4; 8) ;   |OB| = 8.9443
Scalar product OA .OB = 92
Angle ∠ AOB = 9°51'57″ = 0.1722 rad