Line slope calculator 2x+y=16
Straight line given by points A[3; 10] and B[4; 8]
Calculation:
Slope: m = -2Slope-intercept form of line: y = -2x+16
Canonical form of the line equation: 2x+y-16 = 0
Parametric form of the line equation:
x = t+3
y = -2t+10 ; t ∈ R
Slope angle of line: φ = -63°26'6″ = -1.1071 rad
X intercept: x0 = 8
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 7.1554
The length of the segment AB: |AB| = 2.2361
Vector: AB = (1; -2)
Normal vector: n = (2; 1)
Midpoint of the segment AB: M = [3.5; 9]
Perpendicular Bisector equation: x-2y+14.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (4; 8) ; |OB| = 8.9443
Scalar product OA .OB = 92
Angle ∠ AOB = 9°51'57″ = 0.1722 rad