Line slope calculator 6x+2y=38


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[5; 4]

Calculation:

Slope-intercept form of line: y = -3x+19

Canonical form of the line equation: 6x+2y-38 = 0

Parametric form of the line equation:
x = 2t+3
y = -6t+10      ; t ∈ R

Slope: m = -3

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 6.3333

Y intercept: y0 = q = 19

Distance line from the origin: d0 = 6.0083

The length of the segment AB: |AB| = 6.3246

Vector: AB = (2; -6)

Normal vector: n = (6; 2)

Midpoint of the segment AB: M = [4; 7]

Perpendicular Bisector equation: 2x-6y+34 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (5; 4) ;   |OB| = 6.4031
Scalar product OA .OB = 55
Angle ∠ AOB = 34°38'27″ = 0.6046 rad