Line slope calculator 6x+2y=38
Straight line given by points A[3; 10] and B[5; 4]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+19
Canonical form of the line equation: 6x+2y-38 = 0
Parametric form of the line equation:
x = 2t+3
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 6.3333
Y intercept: y0 = q = 19
Distance line from the origin: d0 = 6.0083
The length of the segment AB: |AB| = 6.3246
Vector: AB = (2; -6)
Normal vector: n = (6; 2)
Midpoint of the segment AB: M = [4; 7]
Perpendicular Bisector equation: 2x-6y+34 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (5; 4) ; |OB| = 6.4031
Scalar product OA .OB = 55
Angle ∠ AOB = 34°38'27″ = 0.6046 rad