Line slope calculator 5x+2y=35
Straight line given by points A[3; 10] and B[5; 5]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+17.5
Canonical form of the line equation: 5x+2y-35 = 0
Parametric form of the line equation:
x = 2t+3
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 7
Y intercept: y0 = q = 17.5
Distance line from the origin: d0 = 6.4993
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [4; 7.5]
Perpendicular Bisector equation: 2x-5y+29.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 65
Angle ∠ AOB = 28°18'3″ = 0.4939 rad