Line slope calculator x+y=13
Straight line given by points A[3; 10] and B[5; 8]
Calculation:
Slope: m = -1Slope-intercept form of line: y = -x+13
Canonical form of the line equation: x+y-13 = 0
Parametric form of the line equation:
x = t+3
y = -t+10 ; t ∈ R
Slope angle of line: φ = -45° = -0.7854 rad
X intercept: x0 = 13
Y intercept: y0 = q = 13
Distance line from the origin: d0 = 9.1924
The length of the segment AB: |AB| = 2.8284
Vector: AB = (2; -2)
Normal vector: n = (1; 1)
Midpoint of the segment AB: M = [4; 9]
Perpendicular Bisector equation: 2x-2y+10 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (5; 8) ; |OB| = 9.434
Scalar product OA .OB = 95
Angle ∠ AOB = 15°18'22″ = 0.2671 rad