Line slope calculator 10x+3y=60


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -3.3333x+20

Canonical form of the line equation: 10x+3y-60 = 0

Parametric form of the line equation:
x = 3t+3
y = -10t+10      ; t ∈ R

Slope: m = -3.3333

Slope angle of line: φ = -73°18'3″ = -1.2793 rad

X intercept: x0 = 6

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 5.747

The length of the segment AB: |AB| = 10.4403

Vector: AB = (3; -10)

Normal vector: n = (10; 3)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: 3x-10y+36.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 18
Angle ∠ AOB = 73°18'3″ = 1.2793 rad