Line slope calculator 10x+3y=60
Straight line given by points A[3; 10] and B[6; 0]
Calculation:
Slope: m = -3.3333Slope-intercept form of line: y = -3.3333x+20
Canonical form of the line equation: 10x+3y-60 = 0
Parametric form of the line equation:
x = 3t+3
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -73°18'3″ = -1.2793 rad
X intercept: x0 = 6
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 5.747
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; -10)
Normal vector: n = (10; 3)
Midpoint of the segment AB: M = [4.5; 5]
Perpendicular Bisector equation: 3x-10y+36.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (6; 0) ; |OB| = 6
Scalar product OA .OB = 18
Angle ∠ AOB = 73°18'3″ = 1.2793 rad