Line slope calculator 5x+3y=45
Straight line given by points A[3; 10] and B[6; 5]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+15
Canonical form of the line equation: 5x+3y-45 = 0
Parametric form of the line equation:
x = 3t+3
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 9
Y intercept: y0 = q = 15
Distance line from the origin: d0 = 7.7174
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [4.5; 7.5]
Perpendicular Bisector equation: 3x-5y+24 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 68
Angle ∠ AOB = 33°29'43″ = 0.5846 rad