Line slope calculator 4x+3y=42
Straight line given by points A[3; 10] and B[6; 6]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+14
Canonical form of the line equation: 4x+3y-42 = 0
Parametric form of the line equation:
x = 3t+3
y = -4t+10 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 10.5
Y intercept: y0 = q = 14
Distance line from the origin: d0 = 8.4
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [4.5; 8]
Perpendicular Bisector equation: 3x-4y+18.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (6; 6) ; |OB| = 8.4853
Scalar product OA .OB = 78
Angle ∠ AOB = 28°18'3″ = 0.4939 rad