Line slope calculator 2x+3y=36


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[6; 8]

Calculation:

Slope-intercept form of line: y = -0.6667x+12

Canonical form of the line equation: 2x+3y-36 = 0

Parametric form of the line equation:
x = 3t+3
y = -2t+10      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 18

Y intercept: y0 = q = 12

Distance line from the origin: d0 = 9.9846

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [4.5; 9]

Perpendicular Bisector equation: 3x-2y+4.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (6; 8) ;   |OB| = 10
Scalar product OA .OB = 98
Angle ∠ AOB = 20°10'14″ = 0.352 rad