Line slope calculator 2x+3y=36
Straight line given by points A[3; 10] and B[6; 8]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+12
Canonical form of the line equation: 2x+3y-36 = 0
Parametric form of the line equation:
x = 3t+3
y = -2t+10 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 18
Y intercept: y0 = q = 12
Distance line from the origin: d0 = 9.9846
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [4.5; 9]
Perpendicular Bisector equation: 3x-2y+4.5 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (6; 8) ; |OB| = 10
Scalar product OA .OB = 98
Angle ∠ AOB = 20°10'14″ = 0.352 rad