Line slope calculator 6x+4y=58
Straight line given by points A[3; 10] and B[7; 4]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+14.5
Canonical form of the line equation: 6x+4y-58 = 0
Parametric form of the line equation:
x = 4t+3
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 9.6667
Y intercept: y0 = q = 14.5
Distance line from the origin: d0 = 8.0432
The length of the segment AB: |AB| = 7.2111
Vector: AB = (4; -6)
Normal vector: n = (6; 4)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 4x-6y+22 = 0
Vector OA = (3; 10) ; |OA| = 10.4403
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 61
Angle ∠ AOB = 43°33'21″ = 0.7602 rad