Line slope calculator 4x+5y=62


Enter coordinates of two different points:

Straight line given by points A[3; 10] and B[8; 6]

Calculation:

Slope-intercept form of line: y = -0.8x+12.4

Canonical form of the line equation: 4x+5y-62 = 0

Parametric form of the line equation:
x = 5t+3
y = -4t+10      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 15.5

Y intercept: y0 = q = 12.4

Distance line from the origin: d0 = 9.6828

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [5.5; 8]

Perpendicular Bisector equation: 5x-4y+4.5 = 0


Vector OA = (3; 10) ;   |OA| = 10.4403
Vector OB = (8; 6) ;   |OB| = 10
Scalar product OA .OB = 84
Angle ∠ AOB = 36°25'51″ = 0.6358 rad