Line slope calculator x+4y=11


Enter coordinates of two different points:

Straight line given by points A[3; 2] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -0.25x+2.75

Canonical form of the line equation: x+4y-11 = 0

Parametric form of the line equation:
x = 4t+3
y = -t+2      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 11

Y intercept: y0 = q = 2.75

Distance line from the origin: d0 = 2.6679

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [5; 1.5]

Perpendicular Bisector equation: 4x-y-18.5 = 0


Vector OA = (3; 2) ;   |OA| = 3.6056
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 23
Angle ∠ AOB = 25°33'36″ = 0.4461 rad