Line slope calculator 2x+5y=16


Enter coordinates of two different points:

Straight line given by points A[3; 2] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.4x+3.2

Canonical form of the line equation: 2x+5y-16 = 0

Parametric form of the line equation:
x = 5t+3
y = -2t+2      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 8

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 2.9711

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [5.5; 1]

Perpendicular Bisector equation: 5x-2y-25.5 = 0


Vector OA = (3; 2) ;   |OA| = 3.6056
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 24
Angle ∠ AOB = 33°41'24″ = 0.588 rad