Line slope calculator x+5y=13


Enter coordinates of two different points:

Straight line given by points A[3; 2] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.2x+2.6

Canonical form of the line equation: x+5y-13 = 0

Parametric form of the line equation:
x = 5t+3
y = -t+2      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 13

Y intercept: y0 = q = 2.6

Distance line from the origin: d0 = 2.5495

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [5.5; 1.5]

Perpendicular Bisector equation: 5x-y-26 = 0


Vector OA = (3; 2) ;   |OA| = 3.6056
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 26
Angle ∠ AOB = 26°33'54″ = 0.4636 rad