Line slope calculator x+6y=15


Enter coordinates of two different points:

Straight line given by points A[3; 2] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -0.1667x+2.5

Canonical form of the line equation: x+6y-15 = 0

Parametric form of the line equation:
x = 6t+3
y = -t+2      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 15

Y intercept: y0 = q = 2.5

Distance line from the origin: d0 = 2.466

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [6; 1.5]

Perpendicular Bisector equation: 6x-y-34.5 = 0


Vector OA = (3; 2) ;   |OA| = 3.6056
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 29
Angle ∠ AOB = 27°21' = 0.4773 rad