Line slope calculator x+6y=15
Straight line given by points A[3; 2] and B[9; 1]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+2.5
Canonical form of the line equation: x+6y-15 = 0
Parametric form of the line equation:
x = 6t+3
y = -t+2 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 15
Y intercept: y0 = q = 2.5
Distance line from the origin: d0 = 2.466
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [6; 1.5]
Perpendicular Bisector equation: 6x-y-34.5 = 0
Vector OA = (3; 2) ; |OA| = 3.6056
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 29
Angle ∠ AOB = 27°21' = 0.4773 rad