Line slope calculator 3x+7y=30


Enter coordinates of two different points:

Straight line given by points A[3; 3] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.4286x+4.2857

Canonical form of the line equation: 3x+7y-30 = 0

Parametric form of the line equation:
x = 7t+3
y = -3t+3      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 10

Y intercept: y0 = q = 4.2857

Distance line from the origin: d0 = 3.9392

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [6.5; 1.5]

Perpendicular Bisector equation: 7x-3y-41 = 0


Vector OA = (3; 3) ;   |OA| = 4.2426
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 30
Angle ∠ AOB = 45° = 0.7854 rad