Line slope calculator x+4y=15


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[3; 3] and B[7; 2]

Calculation:

Slope: m = -0.25

Slope-intercept form of line: y = -0.25x+3.75

Canonical form of the line equation: x+4y-15 = 0

Parametric form of the line equation:
x = 4t+3
y = -t+3      ; t ∈ R

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 15

Y intercept: y0 = q = 3.75

Distance line from the origin: d0 = 3.638

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [5; 2.5]

Perpendicular Bisector equation: 4x-y-17.5 = 0

Vector OA = (3; 3) ;   |OA| = 4.2426
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 27
Angle ∠ AOB = 29°3'17″ = 0.5071 rad