Line slope calculator x+5y=18
Straight line given by points A[3; 3] and B[8; 2]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+3.6
Canonical form of the line equation: x+5y-18 = 0
Parametric form of the line equation:
x = 5t+3
y = -t+3 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 18
Y intercept: y0 = q = 3.6
Distance line from the origin: d0 = 3.5301
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [5.5; 2.5]
Perpendicular Bisector equation: 5x-y-25 = 0
Vector OA = (3; 3) ; |OA| = 4.2426
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 30
Angle ∠ AOB = 30°57'50″ = 0.5404 rad