Line slope calculator x-5y=-12


Enter coordinates of two different points:

Straight line given by points A[3; 3] and B[8; 4]

Calculation:

Slope-intercept form of line: y = 0.2x+2.4

Canonical form of the line equation: x-5y+12 = 0

Parametric form of the line equation:
x = 5t+3
y = t+3      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -12

Y intercept: y0 = q = 2.4

Distance line from the origin: d0 = 2.3534

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [5.5; 3.5]

Perpendicular Bisector equation: 5x+y-31 = 0


Vector OA = (3; 3) ;   |OA| = 4.2426
Vector OB = (8; 4) ;   |OB| = 8.9443
Scalar product OA .OB = 36
Angle ∠ AOB = 18°26'6″ = 0.3218 rad