Line slope calculator x-5y=-12
Straight line given by points A[3; 3] and B[8; 4]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+2.4
Canonical form of the line equation: x-5y+12 = 0
Parametric form of the line equation:
x = 5t+3
y = t+3 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -12
Y intercept: y0 = q = 2.4
Distance line from the origin: d0 = 2.3534
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: 5x+y-31 = 0
Vector OA = (3; 3) ; |OA| = 4.2426
Vector OB = (8; 4) ; |OB| = 8.9443
Scalar product OA .OB = 36
Angle ∠ AOB = 18°26'6″ = 0.3218 rad